1.75t^2-32t-0=0

Solution for 1.75t^2-32t-0=0 equation:

1.75t^2-32t-0=0

We add all the numbers together, and all the variables

1.75t^2-32t=0

a = 1.75; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·1.75·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*1.75}=\frac{0}{3.5}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*1.75}=\frac{64}{3.5}
=18+1/3.5
$